1007ICT / 7611ICT - Implementation For The Three Basic Logic Gates - IT/Computer Science Assignment Help

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Assignment Task -

 

Part A: 

The implementation for this part must use only the three basic logic gates (AND, OR, NOT). 

• Each AND gate and each OR gate can have only 2 inputs.  • Each NOT gate can have only 1 input.  

• No other logic gates or circuits are permitted to be used in your circuit  for Part A. 

You are required to implement a circuit where the user (you) can input a value  for the current gear (G) using value (G1, G2, and G3) and a gear to change to  (S) using value (S1, S2, and S3).  

The circuit decodes the G1, G2, G3 and S1, S2, S3 values using a decoder (see lecture notes) made up of only the permitted logic gates to determine if  S = G, or if S = G – 1, or if S = G + 1

 

Part B: 

For this part, the car has a gearbox that can withstand up to a number of  unsuccessful gear changes (N) and it will break if that number is reached. The  number N ranges from 1 to 7 and must be set via a combination of three  separate inputs: N1, N2, and N3. An N value of 0 is not allowed and the  gearbox state is undefined for this case. This means that you will have to set N to be non-zero (1..7) before starting the engine engaging the gearbox. Note: In  Logisim, you can combine the 3 inputs for N into a single 3 bit input.  

Using the same circuit file containing Part A, add additional circuitry to count  how many successful and unsuccessful gear changes have been made. Each time an unsuccessful gear change is made, add 1 to the number of  unsuccessful gear changes. Each time a successful gear change is made, add  1 to the number of successful gear changes.

 

 

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