Highlights
Q1. Answer the following
a. Differentiate between BOD and COD?
b. Briefly discuss how crown corrosion is caused in sanitary sewers?
c. Briefly discuss three factors that lead to non-Ideal flow conditions.
d. For what purposes is Arrhenius equation used in wastewater engineering?
e. Explain how inclined-plate settling works.
Q2. A water sample contains 120.0mg/L !"# and 105.0 mg/L !# at a pH of
8. Estimate the amount of alkalinity consumed when 190 mg/L of alum is added to the water for precipitation.
Q3. Calculate the settling velocity Vs of particles over a 65° inclined-plate settler of length Lp = 2.0m and plate spacing w = 70mm for countercurrent conditions with a uniform water velocity u = 1.1 m/s.
Q4. For a chlorine contact basin with design discharge of 2000m3/d, the experimental data to find the optimal chlorine dosage are presented in the tables below. After analyzing the data, the amount of chlorine to be used was fixed at 35.5kg/d. The data suggest that Chick-Watson form $%! %"= is applicable for inactivation of Giardia, which has lately been a cause of concern for the locality where the basin is installed.
1. Calculate free chlorine residual.
2. To achieve 99% Giardia inactivation, what should be hydraulic detention time T of the contact basin.
|
Dosage (mg/L) |
Residual (mg/L) |
|
0 |
0 |
|
1.4 |
1 |
|
2.9 |
2 |
|
4.3 |
2.97 |
|
5.9 |
3.94 |
Page 1 of 2
7.4 4.3
|
8.8 |
3.7 |
|
10.4 |
2.7 |
|
11.8 |
1.6 |
|
13.4 |
1 |
|
14.5 |
1.7 |
|
16.2 |
2.8 |
|
Free Cl (mg/L) |
Time, min |
Percent Giardia Surviving |
|
0.5 |
10 |
96 |
|
0.5 |
20 |
84 |
|
0.5 |
30 |
74 |
|
0.5 |
50 |
62 |
|
0.5 |
100 |
40 |
|
1.75 |
20 |
50 |
|
1.75 |
25 |
30 |
|
1.75 |
35 |
22 |
|
1.75 |
45 |
15 |
|
1.75 |
55 |
10 |
Q5. A complete-mix activated sludge (CMAS) process is used for secondary treatment of effluent from a primary clarifier. The design influent flowrate to the activated sludge tank is 9 × 10)with a BOD concentration of 320. The plant operating parameters are as follows:
Dimensions of the aeration tank: 10.0m wide by 10.0m long by 4.5m deep; effluent BOD = 15.0mg/L; yield coefficient = 0.55mg VSS/mg BOD removed; endogenous decay rate of microorganisms= 0.050/d; fraction of biomass that remains as cell debris = 0.15 g VSS/g VSS; half velocity constant = 81g BOD/m3; maximum specific growth rate = 1.15g VSS/g VSS-d; bCOD/BOD ratio = 1.6; nbVSS in the influent = negligible; operating temperature = 20°C
Determine:
a. SRT
b. Oxygen demand in kg/d
c. MLVSS in mg/L
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