CIV2206: Combined Stresses The ‘Right hand Screw’ Rule - Engineering Assignment Help

Assignment Task:

Task:

3D Equilibrium (Remember to use the ‘Right hand screw’ rule to define the direction of your moment reactions)

Q1 Referring to Figure Q1 below, determine the reactions at the roller support A, the ball-and-socket joint D, and the tension cable BC supporting the plate shown below (Hibbeler F4-8 Note: All ‘F’ questions in Hibbeler have fully worked answers in the back of the book)). (Ans: FA = 660N, TBC = 352.5N)

Q2 The power line pole shown in Figure Q2 below is subjected to the two cable forces of 300N, each force lying in a plane parallel to the XY plane. If the tension in the guy rope wire AB is 400N, determine the x,y,z components of reaction (moment reactions also) at the fixed base, O, of the pole. (Hibbeler 4-35) (Ans: Mox = 1422Nm, Foy =-424.3N, Fooz = 400N)

Q3 Determine the components of the reaction acting at the smooth journal bearings A,B and C in Figure Q9. (Hint: You will need to decide whether you can ignore the moment components of the reactions) (Ans: Cy =-318.2N, Cz =500N, Bx =-238.65N, Bz =-272.7N, Cz = 500N, Ax = -238.65N, Az = 90.9N)

Bending and Combined Stress Questions

Q4 Determine the moment M that should be applied to the beam in order to create a maximum stress of 30MPa, a) by finding the force resultants of the stress distribution using basic principles. b) By using the flexure formula ? = My/I. (Ans: M=27.34kNm)

Q5. Determine the resultant stress (of the compressive and bending stresses) at points E and F at section a-a. Allow for the offset of the hanger support at point D. (Ans: Point E ?=-1.01MPa; Point F ?=-27.7MPa

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