Highlights
Question 1: Vg cipher hides the statistical patterns of the plain.. from ciphertexts. That the ciphertext letter frequency does. have the pattern of plaintext letter frequency. what is the reason? Answer: Vigenere cipher uses multiple substitution tables. As a direct consequence, the same letter in the plaintext will be encrypted to different ciphertext letters. So, the frequency of a particular letter from the ciphertext will be affected by many letters from the plaintext rather than a single letter.
Argument points:
1) multiple substitution tables:
2) one letter in plaintext becomes different letters in ciphertext:
3) the frequency, of a letter in the ciphertext is affected by different letters from the plainte.
o Sample Question 2: From the lectures. we know that the security of the RSA encryption is based on the hardness of the factoring problem. Explain why if factoring problem is easy then the attacker can derive the FtSA private key d from the RSA public key (n. e) and then decrypt all ciphertexts. Answer: In RSA, the modulo number n is a product of tvvo large prime numbers p and If the factoring problem is easy. then given the product n. ts easy to find p and q. Moreover. the parameters d. e, and n satisfy the relation ed el (mod phi(n)) where phi(n). (p-1)*(q.
1. if the attacker can factor n to get p and q. it will easily compute phi(n) and then find d using e (which is part of the public key). Oni(n) (which she just computed) and the known relation function. After she recovers d. she can use,t to decrypt ciphertexts. Argument points: 1, ed El (mod phi(n)) and phi(n). (p-1).(o-1):
2) factoring n gives p and q. and therefore ohi(n):
3) The decryption exponent d. the only unknown equation can be found.
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